【y#39;+f#39;(x)y=f(x)f#39;(x)求微分方程】

问题：【y#39;+f#39;(x)y=f(x)f#39;(x)求微分方程】

答案：↓↓↓

刘树德的回答：

网友采纳　　y=e^[-∫P(x)dx]{∫Q(x)e^[∫P(x)dx]dx+C}P(x)=f'(x)Q(x)=f(x)f'(x)∫P(x)dx=∫f'(x)dx=f(x)∫Q(x)e^[∫P(x)dx]dx=∫f(x)f'(x)e^f(x)dx=∫f(x)d[e^f(x)]=f(x)e^f(x)-∫e^f(x)d(f(x))=f(x)e^f(x)-e^f(x)所以y=e^[-f(...