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问题：已知3x+2y=4+z,2x+2z=6+y,问是否存在x、y、z的正整数值,使得x+y+z
答案：↓↓↓ 陈水桥的回答： 网友采纳 假设x+y+zz=3x+2y-42x+2z=6+y===>y=2x+2z-6=2x-6+6x+4y-8=8x-14+4y===>3y=14-8xz=3x+2y-4===>3z=9x+6y-12=9x-12+28-16x=16-7x3x+3y+3z=3x+14-8x+16-7x=30-12xx+y+z=10-4x10-4x3（成立）x=1时,3y=14-8x===>y=... | 
