【数列{an},{bn}满足anbn=1,an=n2+3n+2,则{bn}的前十项的和为】
<p>问题：【数列{an},{bn}满足anbn=1,an=n2+3n+2,则{bn}的前十项的和为】<p>答案：↓↓↓<p class="nav-title mt10" style="border-top:1px solid #ccc;padding-top: 10px;">李小舟的回答：<div class="content-b">网友采纳 bn=1/(n2+3n+2) =1/((n+1)(n+2)) S10=1/(2*3)+1/(3*4).+1/(11*12) =1/2-1/3+1/3-.+1/11-1/12 =1/2-1/12 =5/12
页:
[1]