以(y-c2)^2=4c1x为通解的微分方程
<p>问题：以(y-c2)^2=4c1x为通解的微分方程<p>答案：↓↓↓<p class="nav-title mt10" style="border-top:1px solid #ccc;padding-top: 10px;">陈志新的回答：<div class="content-b">网友采纳 ∵(y-C2)^2=4C1x==>2(y-C2)y'=4C1(等式两端对x求导数) ==>y-C2=2xy'(代入通解化简) ==>y'=2xy''+2y'(等式两端对x求导数) ==>2xy''+y'=0 ∴所求微分方程是2xy''+y'=0.
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