【y#39;+f#39;(x)y=f(x)f#39;(x)求微分方程】
<p>问题：【y#39;+f#39;(x)y=f(x)f#39;(x)求微分方程】<p>答案：↓↓↓<p class="nav-title mt10" style="border-top:1px solid #ccc;padding-top: 10px;">刘树德的回答：<div class="content-b">网友采纳 y=e^[-∫P(x)dx]{∫Q(x)e^[∫P(x)dx]dx+C}P(x)=f'(x)Q(x)=f(x)f'(x)∫P(x)dx=∫f'(x)dx=f(x)∫Q(x)e^[∫P(x)dx]dx=∫f(x)f'(x)e^f(x)dx=∫f(x)d=f(x)e^f(x)-∫e^f(x)d(f(x))=f(x)e^f(x)-e^f(x)所以y=e^[-f(...
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