求解初值问题y#39;#39;-2y#39;-3y＝0；y(0)＝0,y#39;(0)＝-1
<p>问题：求解初值问题y#39;#39;-2y#39;-3y＝0；y(0)＝0,y#39;(0)＝-1<p>答案：↓↓↓<p class="nav-title mt10" style="border-top:1px solid #ccc;padding-top: 10px;">陆祖康的回答：<div class="content-b">网友采纳 特征方程 r^2-2r-3=0 r1=3,r1=-1 y=c1e^(3x)+c2e^(-x) y(0)=0C1+C2=0 y'(0)=-13C1-C2=-1 C1=-1/4,C2=1/4 y=(-1/4)e^(3x)+(1/4)e^(-x)
页:
[1]