已知:a^2b^2c^22ab2bc2ca=0,化简代数式1/2a^3-1/2ab^2-1/2ac^2.
<p>问题：已知:a^2b^2c^22ab2bc2ca=0,化简代数式1/2a^3-1/2ab^2-1/2ac^2.<p>答案：↓↓↓<p class="nav-title mt10" style="border-top:1px solid #ccc;padding-top: 10px;">孙小兵的回答：<div class="content-b">网友采纳 a平方+b平方+c平方+2ab+2bc+2ca=0 (a+b+c)^2=0 a+b+c=0 a=-(b+c) 1/2a^3-1/2ab^2-1/2ac^2=a/2(a^2-b^2-c^2) =a/2[(b+c)^2-(b^2+c^2)] =a/2(2bc) =abc
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