设总体X的概率密度为：f(x,θ)=e的[-(x-θ)]次方,x≥θ；0,x
<p>问题：设总体X的概率密度为：f(x,θ)=e的[-(x-θ)]次方,x≥θ；0,x<p>答案：↓↓↓<p class="nav-title mt10" style="border-top:1px solid #ccc;padding-top: 10px;">杭柏林的回答：<div class="content-b">网友采纳 EX=∫(上+∞下θ)xf(x,θ)dx=∫(上+∞下θ)xe^[-(x-θ)]dx =-(xe^[-(x-θ)]|(上+∞下θ)-∫(上+∞下θ)e^[-(x-θ)]dx) =-θ-1=µ θ=-µ-1 θ^=-￣X-1(X左边横线在X上方) 其中￣X=1/n∑(从1到n)Xi
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