log(4)7*log(49)25*log(125)64用换底公式怎样计?
<p>问题：log(4)7*log(49)25*log(125)64用换底公式怎样计?<p>答案：↓↓↓<p class="nav-title mt10" style="border-top:1px solid #ccc;padding-top: 10px;">马敬广的回答：<div class="content-b">网友采纳 log4(7)×log49(25)×log125(64) =(lg7/lg4)×(lg25/lg49)×(lg64/lg125) =(lg7/g4)×[(2lg5)/(2lg7)]×[(3lg4)/(3lg5)] =(lg7/lg4)×(lg5/lg7)×(lg4/lg5) =1
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