微分方程dy/dx=y/(x+y^2)的通解?
<p>问题：微分方程dy/dx=y/(x+y^2)的通解?<p>答案：↓↓↓<p class="nav-title mt10" style="border-top:1px solid #ccc;padding-top: 10px;">黄烈德的回答：<div class="content-b">网友采纳 设t=x/y 则x=ty dx=tdy+ydt dy/dx=y/(x+y^2)=> dx/dy=x/y+y把dx代入 t+ydt/dy=t+y ydt/dy=y dt/dy=1 t=y+C(C是常数) x=y^2+Cy
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