设f(x)在x=2处可导,且f#39;(2)=1,则limh→0[f(2+h)-f(2-h)]/h等于多少,
<p>问题：设f(x)在x=2处可导,且f#39;(2)=1,则limh→0/h等于多少,<p>答案：↓↓↓<p class="nav-title mt10" style="border-top:1px solid #ccc;padding-top: 10px;">耿峰的回答：<div class="content-b">网友采纳 由导数的定义可知f(x)在x=2处可导,且f'(2)=1,就是说lim(f(2+h)-f(2))/h=1 于是,lim/h =lim/h =lim(f(2+h)-f(2))/h+(f(2-h)-f(2))/(-h) =f'(2)+f'(2) =1+1 =2
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