已知象函数F(s)=2s+1/(s+3)^2,求原函数f(t)的初值f(0+)的终值f(oo).
<p>问题：已知象函数F(s)=2s+1/(s+3)^2,求原函数f(t)的初值f(0+)的终值f(oo).<p>答案：↓↓↓<p class="nav-title mt10" style="border-top:1px solid #ccc;padding-top: 10px;">李秋锦的回答：<div class="content-b">网友采纳 极点在复平面左侧s=-3 根据初值和终值定理, f(0+)=lim(s->+∞)s*F(s)=lims*(2s+1)/(s+3)^2=2 f(+∞)=lim(s->0)s*F(s)=0
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