（8）溶液的配制——2021-2022学年人教版化学九年级水和溶液专题小练
※题型：单选题※知识点：单选题※试题难度：中等<br>用氯化钠固体和蒸馏水配制100g10%的氯化钠溶液,不需要的仪器是( )<br>A.玻璃棒 B.蒸发皿 C.烧杯 D.电子天平<br>答案<br><img src="https://picture2.zhihuicn.com/answer/2/5/2021/dd19c3464e2c4558ac96fe0ca2fcb1c6/76900E09FAB5EBA344B8EA84E844FF07.png"><br>解析<br>略<br>※题型：单选题※知识点：单选题※试题难度：中等<br>某同学配制100g质量分数为11%的葡萄糖溶液,下列操作会导致所配溶液浓度偏高的是( )<br>A.用托盘天平称葡萄糖时,砝码放在左盘<br>B.转移葡萄糖时,纸上有少量残留<br>C.用量筒量取水时,俯视液面<br>D.配好溶液装入试剂瓶时,有少量洒出<br>答案<br><img src="https://picture2.zhihuicn.com/answer/2/5/2021/f72df53553704f4abcb39c3968ccb932/06CA09E70C17EF8BA2D3B8C70D693953.png"><br>解析<br><img src="https://picture2.zhihuicn.com/explain/2/5/2021/adb8d8875282409eac59392eab6eae42/11B0A3446DB5E8AE9C63B16FDC5A8095.png"><br><br>※题型：单选题※知识点：单选题※试题难度：较易<br>用20mL质量分数为70%的硫酸溶液(密度为1.6<img src="https://picture2.zhihuicn.com/testImage/2/2021/7/29/A0845D95AC2394208DB655136C953899.png"><br>),配制质量分数为28%的硫酸溶液(密度为1.2<img src="https://picture2.zhihuicn.com/testImage/2/2021/7/29/A0845D95AC2394208DB655136C953899.png"><br>),下列仪器中①烧杯②滴管③漏斗④量筒⑤玻璃棒⑥天平⑦酒精灯,需要用到的是( )<br>A.②④⑥⑦ B.①②④⑤ C.①③⑤⑦ D.①③④⑥<br>答案<br><img src="https://picture2.zhihuicn.com/answer/2/5/2021/5b3b88f84655487aa05f9edef3adfc46/76900E09FAB5EBA344B8EA84E844FF07.png"><br>解析<br><img src="https://picture2.zhihuicn.com/explain/2/5/2021/35ea901a2af64874a8f9ac156ce94df4/4DE38BA20FC2A9E03A9192CAC1D8A743.png"><br><br>※题型：单选题※知识点：单选题※试题难度：中等<br>如图为配制溶质质量分数为10%的氯化钠溶液的实验图。有关说法中正确的是( )<img src="https://picture2.zhihuicn.com/testImage/2/2021/7/29/04EC6EFEEC820F70836A3A4798FDC680.png"><br>A.正确的实验操作顺序为④②⑤⑥①③<br>B.图②④⑥中的操作有错误<br>C.若量取水时,读数如图⑥,则配制的溶液浓度偏大<br>D.所用的烧杯内壁沾有水,对配制的溶液浓度无影响<br>答案<br><img src="https://picture2.zhihuicn.com/answer/2/5/2021/7b9e8dacd3fb4fd9b308bd6898dccc71/76900E09FAB5EBA344B8EA84E844FF07.png"><br>解析<br><img src="https://picture2.zhihuicn.com/explain/2/5/2021/afc87be9902a4b61b0b9b0f0bc138138/0C993E35533216EACC8FA91C6D803523.png"><br><br>※题型：单选题※知识点：单选题※试题难度：中等<br>现在实验室只有37%的浓盐酸,要配制148g溶质质量分数为5%的稀盐酸,需蒸馏水的质量为( )<br>A.20g B.25g C.140.6g D.128g<br>答案<br><img src="https://picture2.zhihuicn.com/answer/2/5/2021/ea4d2ccbdb264f09a1391effed83ab89/01A39E48B8A67989A23F6887F26FCC64.png"><br>解析<br><img src="https://picture2.zhihuicn.com/explain/2/5/2021/8bc16b35ab434262a14c6c5eaf9e4374/BA7E1910AF12EB8E0F12B0B059E4E33C.png"><br><br>※题型：填空题※知识点：填空题※试题难度：中等<br>某校环保小组为监测某厂排出的污水中某重金属离子的含量,需配制<br>11%<br>的氯化钠溶液<br>100g<br>。小<br>明同学<br>按下图步骤进行了操作:<br><img src="https://picture2.zhihuicn.com/testImage/2/2021/7/29/AA4DF6AEEFDE707AECFB28200228A44E.png"><br>1.图E中玻璃棒的作用是。<br>2.上述操作步骤中有错误的是(填序号),请选择一处错误操作予以纠正:。<br>3.按上图所示操作,最终烧杯E中配得的溶液质量与100g的关系是(填“大于”“小于”或“无法确定”)。<br>4.上述错误导致所配溶液的溶质质量分数(填“大于”“小于”或“等于”)11%。<br>答案<br><img src="https://picture2.zhihuicn.com/answer/2/5/2021/7a12ed6683da4df5a900e04bc0a92103/717E126FBDE11848A0F23B47A782B9AE.png"><br>解析<br><img src="https://picture2.zhihuicn.com/explain/2/5/2021/3f233089f6104489aa9941d472437f11/8995AC7DF0596BE5B883EED731853C72.png"><br><br>
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