GMAT3月新题（一）
<p> 航空公司的竞争系数是2</p><p> 比60小的数中，与60没有相同因子的数有15个!</p><p> 全由0，1组成，求这些数字的和的最大<span word="prime">prime</span> <span word="factor">factor</span>是101</p><p> 2.<span word="ps">ps</span> <span word="a">a</span>,<span word="b">b</span>是正整数，<span word="a">a</span>-<span word="b">b</span>和<span word="a">a</span>/<span word="b">b</span>都是偶数，问一下哪项是奇数，</p><p> 选项有<span word="a">a</span>/2,<span word="b">b</span>/2,/2,/2, /2</p><p> <span word="V">V</span>2<span word="a">a</span>,<span word="b">b</span>是正整数，<span word="a">a</span>-<span word="b">b</span>和<span word="a">a</span>/<span word="b">b</span>都是偶数，问一下哪项是奇数</p><p> <span word="A">A</span>. <span word="a">a</span>/2</p><p> <span word="B">B</span>. <span word="b">b</span>/2</p><p> <span word="C">C</span>. /2</p><p> <span word="D">D</span>. /2</p><p> <span word="E">E</span>. /2</p><p> 根据题目，<span word="a">a</span>-<span word="b">b</span>为偶数，说明<span word="a">a</span>、<span word="b">b</span>一定同奇偶。然后<span word="a">a</span>/<span word="b">b</span>也是偶数，那<span word="a">a</span>、<span word="b">b</span>一定都是偶数了。而且因为<span word="a">a</span>/<span word="b">b</span>是偶数，所以可以肯定的是<span word="a">a</span>至少是4的倍数。</p><p> 于是我们再来看选项：</p><p> <span word="a">a</span>/2 偶数;</p><p> <span word="b">b</span>/2 不确定;</p><p> /2,这里我们要注意，<span word="a">a</span>/2一定是偶数，而2/2=1为奇数，所以<span word="a">a</span>/2+1一定就是个奇数了。</p><p> /2因为我们只知道<span word="b">b</span>是偶数，所以这选项也是不能确定;</p><p> /2也不能确定。</p><p> 所以最后选/2</p><p> 9、是否可以定义<span word="x">x</span>@<span word="y">y</span>=<span word="y">y</span>@<span word="x">x</span></p><p> </p><p> 1)<span word="x">x</span>@1=<span word="x">x</span>^2+<span word="x">x</span>+1</p><p> 2) <span word="x">x</span>@<span word="y">y</span>=<span word="x">x</span>^2+<span word="y">y</span>^2+<span word="xy">xy</span></p><p> 【<span word="Kathycong">Kathycong</span>】</p><p> <span word="LZ">LZ</span>~我有问题想讨论~第9题的第一个条件~</p><p> 通过这个条件我们可以知道1和<span word="X">X</span>对调结果不一样，那是不是就能得出:不能定义<span word="X">X</span>@<span word="Y">Y</span>=<span word="Y">Y</span>@<span word="X">X</span>呢?</p>
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