费费数学宝典详解版(二)
<p> 6、<span word="P">P</span>为627的倍数，且<span word="P">P</span>个位为4，<span word="Q">Q</span>=<span word="P">P</span>/627，问：<span word="Q">Q</span>个位为几?</p><p> 【答案】2</p><p> 【思路】<span word="P">P</span>=627<span word="K">K</span>，因<span word="P">P</span>的个位为4，所以<span word="K">K</span>的个位一定为2，<span word="Q">Q</span>=<span word="P">P</span>/627=627<span word="K">K</span>/627=<span word="K">K</span></p><p> 所以<span word="Q">Q</span>的个位为2。</p><p> 7、一直线<span word="L">L</span>过点<span word="A">A</span>，<span word="B">B</span>，坐标原点为<span word="O">O</span>，点<span word="P">P</span>为三角形<span word="OAB">OAB</span>中的一点，问：<span word="y">y</span></p>
页:
[1]