问几道一元一次方程题(1)y+1/2=2-y/3(2)2x+5/6-3x2/8=1(3)2.4-(x-4/2)=3/5x(1)y+(1/2)=(2-y/3)(2)(2x+5/6)-(3x-2/8)=1(3)2.4-(x-4/2)=(3/5)x
<p>问题：问几道一元一次方程题(1)y+1/2=2-y/3(2)2x+5/6-3x2/8=1(3)2.4-(x-4/2)=3/5x(1)y+(1/2)=(2-y/3)(2)(2x+5/6)-(3x-2/8)=1(3)2.4-(x-4/2)=(3/5)x<p>答案：↓↓↓<p class="nav-title mt10" style="border-top:1px solid #ccc;padding-top: 10px;">沈熙的回答：<div class="content-b">网友采纳 (1)y+1/2=2-y/3 4/3y=-1/2y=-1/2*3/4y=-3/8 (2)2x+5/6-3x2/8=1 11/4x=1-5/6x=1/6*4/11x=4/66 (3)2.4-(x-4/2)=3/5x 4.4-x=3/5x8/5x=4.4x=11/4
页:
[1]