解方程:(-3x)^2-(2x+1)(3x-2)-3(x+2)(x-2)=0设m^2-m+1=0,求m^3-3m^2+3m-2023的值.
<p>问题：解方程:(-3x)^2-(2x+1)(3x-2)-3(x+2)(x-2)=0设m^2-m+1=0,求m^3-3m^2+3m-2023的值.<p>答案：↓↓↓<p class="nav-title mt10" style="border-top:1px solid #ccc;padding-top: 10px;">别晓武的回答：<div class="content-b">网友采纳 1）:(-3x)^2-(2x+1)(3x-2)-3(x+2)(x-2)=09x^2-6x^2+x+2-3x^2+12=0x=-14设m^2-m+1=0,求m^3-3m^2+3m-2011的值.m^3-3m^2+3m-2011=m(m^2--3m+3)-2011=m{(m^2--m+1)-2m+2}-2011=m(-2m+2)-2011=(-2m^2+2m)-2011-2{(m^2-m+1...
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