若xy为有理数,且x^2+y^2+1/2=x+y,求x+y因式分解：（m^2+2m)^2-(2m+4n^2)^2023(a-b)^2-225(a+b)^2
<p>问题：若xy为有理数,且x^2+y^2+1/2=x+y,求x+y因式分解：（m^2+2m)^2-(2m+4n^2)^2023(a-b)^2-225(a+b)^2<p>答案：↓↓↓<p class="nav-title mt10" style="border-top:1px solid #ccc;padding-top: 10px;">戴京东的回答：<div class="content-b">网友采纳 x^2+y^2-x-y+1/4+1/4=0(x^2-x+1/4)+(y^2-y+1/4)=0(x-1/2)^2+(y-1/2)^2=0x=1/2y=1/2x+y=1/2+1/2=1(m^2+2m)^2-(4m+4n^2)^2=[(m^2+2m)+(4m+4n^2)][(m^2+2m)-(4m+4n^2)]=(m^2+6m+4n^2)(m^2-2m-4n^2)144(a-b)^2-225(a+b)^...
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