(b-c)(c-a)分之a-b+（c-a）(a-b)分之b-c+(a-b)(b-c)分之c-a的值能否为0
<p>问题：(b-c)(c-a)分之a-b+（c-a）(a-b)分之b-c+(a-b)(b-c)分之c-a的值能否为0<p>答案：↓↓↓<p class="nav-title mt10" style="border-top:1px solid #ccc;padding-top: 10px;">吉兵的回答：<div class="content-b">网友采纳 (b-c)(c-a)分之a-b+（c-a）(a-b)分之b-c+(a-b)(b-c)分之c-a=(a-b)/(b-c)(c-a)-(b-c)/(a-c)(a-b)-(a-c)/(a-b)(b-c)=[(a-b)²-(b-c)²-(a-c)²]/[(a-b)(b-c)(a-c)]=(a²-2ab+b²-b²+2bc-c&...
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