已知:a/a-b=2,求(a的平方+ab)(a-5b)/(a-b)(a的平方-5ab)的值.
<p>问题：已知:a/a-b=2,求(a的平方+ab)(a-5b)/(a-b)(a的平方-5ab)的值.<p>答案：↓↓↓<p class="nav-title mt10" style="border-top:1px solid #ccc;padding-top: 10px;">孙凤池的回答：<div class="content-b">网友采纳 a/(a-b)=2 (a-b)/a=0.51-b/a=0.5b/a=0.5 (a^2+ab)(a-5b)/((a-b)(a^2-5ab)) =a(a+b)(a-5b)/(a(a-b)(a-5b)) =(a+b)/(a-b) =a/(a-b)+b/(a-b) =2+b/(a-b) (a-b)/b=a/b-1=1/0.5-1=1 所以原式=2+1/1=3
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