【将下列三角函数转化为锐角三角函数sin(-5/3π);tan(632°24#39;);tan17π/6】
<p>问题：【将下列三角函数转化为锐角三角函数sin(-5/3π);tan(632°24#39;);tan17π/6】<p>答案：↓↓↓<p class="nav-title mt10" style="border-top:1px solid #ccc;padding-top: 10px;">乐可锡的回答：<div class="content-b">网友采纳 sin(-5/3π)＝－sin5π/3＝－sin(2π－π/3)＝sinπ/3 tan(632°24')＝tan(720－87°36')＝tan(－87°36')＝－tan87°36' tan17π/6＝tan(2π＋5π/6)＝tan5π/6＝tan(π－π/6)＝－tanπ/6
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