meili 发表于 2022-10-27 15:52:09

【11点前务必答出!)1:4a(x-2)amp;sup2;-2b(2-x)amp;sup3;2:(2x+3)(x-2y)+(x-2y)(x+1)+(2y-x)3:mamp;sup2;(aamp;sup2;+bamp;sup2;)-mn(bamp;sup2;+aamp;sup2;)+mp(aamp;sup2;+bamp;sup2;)4:6p(x-1)amp;sup2;-8pamp;sup2;(1-x

<p>问题:【11点前务必答出!)1:4a(x-2)amp;sup2;-2b(2-x)amp;sup3;2:(2x+3)(x-2y)+(x-2y)(x+1)+(2y-x)3:mamp;sup2;(aamp;sup2;+bamp;sup2;)-mn(bamp;sup2;+aamp;sup2;)+mp(aamp;sup2;+bamp;sup2;)4:6p(x-1)amp;sup2;-8pamp;sup2;(1-x)amp;sup2;5:(a-b)的2n次方-(b-a)2n+1次方】
<p>答案:↓↓↓<p class="nav-title mt10" style="border-top:1px solid #ccc;padding-top: 10px;">李红松的回答:<div class="content-b">网友采纳  1:4a(x-2)²-2b(2-x)³=4a(x-2)²+2b(x-2)³=2(x-2)²=2(x-2)²(bx+2a-2b)2:(2x+3)(x-2y)+(x-2y)(x+1)+(2y-x)=(2x+3)(x-2y)+(x-2y)(x+1)-(x-2y)=(x-2y)[(2x+3)+(x+1)-1]=3(x-2y...
页: [1]
查看完整版本: 【11点前务必答出!)1:4a(x-2)amp;sup2;-2b(2-x)amp;sup3;2:(2x+3)(x-2y)+(x-2y)(x+1)+(2y-x)3:mamp;sup2;(aamp;sup2;+bamp;sup2;)-mn(bamp;sup2;+aamp;sup2;)+mp(aamp;sup2;+bamp;sup2;)4:6p(x-1)amp;sup2;-8pamp;sup2;(1-x