【怎样用matlab求解复杂的微分方程组d2x/dt2=(x^2+3x)(dy/dt)d2y/dt2=-(x^2+3x)(dx/dt)当t=0时,x(0)=0,y(0)=0(dx/dt)(0)=a,(dy/dt)(0)=a(d2x/dt2)(0)=a,(d2y/dt2)(0)=a先要得到x,y分别关于t的表达式,然后得到y关于x的表达式初值】
<p>问题：【怎样用matlab求解复杂的微分方程组d2x/dt2=(x^2+3x)(dy/dt)d2y/dt2=-(x^2+3x)(dx/dt)当t=0时,x(0)=0,y(0)=0(dx/dt)(0)=a,(dy/dt)(0)=a(d2x/dt2)(0)=a,(d2y/dt2)(0)=a先要得到x,y分别关于t的表达式,然后得到y关于x的表达式初值】<p>答案：↓↓↓<p class="nav-title mt10" style="border-top:1px solid #ccc;padding-top: 10px;">李炳才的回答：<div class="content-b">网友采纳 =dsolve('D2x=(x*x+3*x)*Dy','D2y=-(x*x+3*x)*Dx','x(0)=0','y(0)=0','Dx(0)=a','Dy(0)=a','D2x(0)=a','D2y(0)=a')%%%%%%%%%%%%%%%%%%%%%%%%%%%设定的X(1)=dx/dt;x(2)=x;x(3)=dy/dt;x(4)=y;%%%%%%%functiondx=...
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