利用拉氏变换解常微分方程的初值问题{y#39;-3y#39;#39;+2y=e-ty(0)=0,y#39;(0)=1}-t为上标
<p>问题：利用拉氏变换解常微分方程的初值问题{y#39;-3y#39;#39;+2y=e-ty(0)=0,y#39;(0)=1}-t为上标<p>答案：↓↓↓<p class="nav-title mt10" style="border-top:1px solid #ccc;padding-top: 10px;">董玉涛的回答：<div class="content-b">网友采纳 记Y(s)=L则L=sY(s)-y(0)=sY(s)L=s^2*Y(s)-sy(0)-y'(0)=s^2*Y(s)-1L=1/(s+1)所以有sY-3(s^2*Y-1)+2Y=1/(s+1)得：Y(s)=1/(s^2-1)所以Y(t)=sinh(t)...
页:
[1]