求微积分y#39;#39;=3/2y^2满足初始条件y|(x=0)=1,y#39;|（x=0)=1的特解.
<p>问题：求微积分y#39;#39;=3/2y^2满足初始条件y|(x=0)=1,y#39;|（x=0)=1的特解.<p>答案：↓↓↓<p class="nav-title mt10" style="border-top:1px solid #ccc;padding-top: 10px;">潘庆谊的回答：<div class="content-b">网友采纳 令y'=p(y),则y''=p'(y)*dy/dx=p'p,则原方程化为：p'p=3/2y²,则pdp=3/2y²dy两边积分得：1/2p²=1/2y³+C1由x=0时,y=1,y'=1,即p=1,代入上式得：C1=0则：p²=y³,则p=y^(3/2)即：dy/dx=y^(3/...
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