Acos(ωt+α)+Bsin(ωt+β)=CCos(ωt+γ)等号左边已知,C和γ怎么求?A,ω,α,B,β已知
<p>问题：Acos(ωt+α)+Bsin(ωt+β)=CCos(ωt+γ)等号左边已知,C和γ怎么求?A,ω,α,B,β已知<p>答案：↓↓↓<p class="nav-title mt10" style="border-top:1px solid #ccc;padding-top: 10px;">雷雨成的回答：<div class="content-b">网友采纳 先求C;Acos(ωt+α)+Bsin(ωt+β)=Ccos(ωt+γ)*将*式两边分别对t求导,得:-Asin(ωt+α)+Bcos(ωt+β)=-Csin(ωt+γ)**(ω约去)*和**式平方相加,得：C^2=A^2+B^2+2AB[cos(ωt+α)sin(ωt+β)-sin(ωt+...
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