1.2[x-3]^2=[2x-5][2x+1]2.2y^2+8y+8=03.-3/2x^2+x+2=0
<p>问题：1.2^2=2.2y^2+8y+8=03.-3/2x^2+x+2=0<p>答案：↓↓↓<p class="nav-title mt10" style="border-top:1px solid #ccc;padding-top: 10px;">刘培桐的回答：<div class="content-b">网友采纳 1.2^2=2x^2-12x+18=4x^2+2x-10x-52x^2+4x-23=0x^2+2x=23/2^2=25/2x+1=+/-5/根2x1=-1+5/根2x2=-1-5/根22.2y^2+8y+8=0y^2+4y+4=0^2=0y=-23.-3/2x^2+x+2=0x^2-2/3x-4/3=0^2=4/3...
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