求值域y=x∧2-3x+4f（x）=√x∧2-2x+4
<p>问题：求值域y=x∧2-3x+4f（x）=√x∧2-2x+4<p>答案：↓↓↓<p class="nav-title mt10" style="border-top:1px solid #ccc;padding-top: 10px;">彭宇的回答：<div class="content-b">网友采纳 y=x∧2-3x+4=(x-3/2)²+7/4;∵(x-3/2)²≥0;∴y≥0+7/4=7/4;所以值域为[7/4,+∞);f（x）=√x∧2-2x+4=√(x-1)²+3;∵(x-1)²≥0;∴√(x-1)²+3≥√3;所以值域为[√3,+∞)很高兴为您解答,skyhunt...
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