meili 发表于 2022-10-27 15:40:12

1/x+1/y=1/61/y+1/z=1/10(1/x+1/z)*5=2/3

<p>问题:1/x+1/y=1/61/y+1/z=1/10(1/x+1/z)*5=2/3
<p>答案:↓↓↓<p class="nav-title mt10" style="border-top:1px solid #ccc;padding-top: 10px;">方雄的回答:<div class="content-b">网友采纳  1/x+1/y=1/6(1)  1/y+1/z=1/10(2)  (1/x+1/z)*5=2/3(3)  (3)式两边除以5得:1/x+1/z=2/15(4)  (1)-(2)得1/x-1/z=1/15(5)  (4)+(5)得1/x=1/10  解得x=10  y=15  z=30
页: [1]
查看完整版本: 1/x+1/y=1/61/y+1/z=1/10(1/x+1/z)*5=2/3