导数运算//(u*1/v)#39;怎么化简成u#39;*1/v+u*(1/v)#39;?(u/v)#39;=(u*1/v)#39;=u#39;*1/v+u*(1/v)#39;=u#39;*1/v+u*(-1/vamp;#178;)*v#39;=u#39;/v-u*v#39;/vamp;#178;=(u#39;*v-u*v#39;)/vamp;#178;
<p>问题:导数运算//(u*1/v)#39;怎么化简成u#39;*1/v+u*(1/v)#39;?(u/v)#39;=(u*1/v)#39;=u#39;*1/v+u*(1/v)#39;=u#39;*1/v+u*(-1/vamp;#178;)*v#39;=u#39;/v-u*v#39;/vamp;#178;=(u#39;*v-u*v#39;)/vamp;#178;<p>答案:↓↓↓<p class="nav-title mt10" style="border-top:1px solid #ccc;padding-top: 10px;">董为众的回答:<div class="content-b">网友采纳 你把1/v当成一个函数f(x)=1/v(x),然后用乘法的法则展开就行了
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