meili 发表于 2022-10-27 15:18:47

已知当x趋向于0时,∫(x,-x)(sin(t)+sin(t^2))d(t)与a(x^k)是等价无穷小,则()A.a=3,k=3/2B.a=2/3,k=3C.a=3,k=2/3D.a=3/2,k=3∫(x,-x)(sin(t)+sin(t^2))d(t)中(x,-x)顺序弄反了,应该是(-x,x)

<p>问题:已知当x趋向于0时,∫(x,-x)(sin(t)+sin(t^2))d(t)与a(x^k)是等价无穷小,则()A.a=3,k=3/2B.a=2/3,k=3C.a=3,k=2/3D.a=3/2,k=3∫(x,-x)(sin(t)+sin(t^2))d(t)中(x,-x)顺序弄反了,应该是(-x,x)
<p>答案:↓↓↓<p class="nav-title mt10" style="border-top:1px solid #ccc;padding-top: 10px;">代光发的回答:<div class="content-b">网友采纳  反不反都不影响解题,再说谁知道你括号里是上限在前还是下限在前啊……  积分里sint是奇函数对称区间积分,为0,直接拿掉.剩sin(t^2)是偶函数,对称区间积分等于2倍的0到x积分.求导后为2sin(x^2)∽2x^2.  a(x^k)求导后为ak(x^(k-1)),比较得ak=2,k-1=2.选B
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查看完整版本: 已知当x趋向于0时,∫(x,-x)(sin(t)+sin(t^2))d(t)与a(x^k)是等价无穷小,则()A.a=3,k=3/2B.a=2/3,k=3C.a=3,k=2/3D.a=3/2,k=3∫(x,-x)(sin(t)+sin(t^2))d(t)中(x,-x)顺序弄反了,应该是(-x,x)