验证(x^2-2xy+y^2)dx-(x^2-2xy-y^2)dy是某个二元函数u=u(x,y)的全微分,并求u=u(x,y)
<p>问题：验证(x^2-2xy+y^2)dx-(x^2-2xy-y^2)dy是某个二元函数u=u(x,y)的全微分,并求u=u(x,y)<p>答案：↓↓↓<p class="nav-title mt10" style="border-top:1px solid #ccc;padding-top: 10px;">陈业仙的回答：<div class="content-b">网友采纳
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