已知f(x)=log4(4^x+1)+kx(k为实数）是偶函数
<p>问题：已知f(x)=log4(4^x+1)+kx(k为实数）是偶函数<p>答案：↓↓↓<p class="nav-title mt10" style="border-top:1px solid #ccc;padding-top: 10px;">边二曼的回答：<div class="content-b">网友采纳 f(-x)=log4(4^(-x)+1)-kx =log4[(4^x+1)/4^x]-kx =log4(4^x+1)-x-kx =log4(4^x+1)-(k+1)x =log4(4^x+1)+kx=f(x) =>-(k+1)=k =>k=-1/2.
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